KSET Final Answer Key 2023 released at cetonline.karnataka.gov.in, direct link to download – Times of India
[ad_1]
The KSET 2023 final answer key has been issued for 42 different subject papers.After receiving objections from candidates, the exam authority issued revised answer keys for 22 subjects of KSET 2023. Students were given the opportunity to submit their objections against the provisional answer key till February 17. The provisional answer key was released on January 29.
“KSET-2023 examination was conducted by the authority on 13.01.2024 for 42 different subject papers. The final key answers for all the 42 different subject papers have been published on the website of the authority for the information of the candidates,” reads the official notification.
Candidates can refer to the below-mentioned step-by-step process to download the Karnataka State Eligibility Test 2024 final answer keys for various subjects from the official website. A direct link to check the same is also provided below.
How to download KSET Final Answer Key 2023?
Step 1: Visit the KEA website at https://cetonline.karnataka.gov.in/kea/
Step 2: Click on the “Admissions” tab and then select “KSET”.
Step 3: Look for a link titled “KSET 2023 Final Answer Key” or something similar.
Step 4: This will likely display a list of answer keys for all the subjects tested.
Step 5: Click on the subject you appeared for in the KSET exam.
Step 6: The KSET 2023 answer key PDF will be displayed on your screen.
Step 7: Download the PDF and save it for your reference.
Direct Link: Download Final Answer Key
KSET 2023 Exam Date & Pattern
The KSET 2023 examination was held on January 13 to select assistant professors for state universities. The exam was divided into two sessions: Paper 1 was conducted from 10 AM to 11 AM, lasting one hour, while Paper 2 was held from 12 PM to 2 PM, spanning two hours.
The examination was structured to carry a total of 300 marks, with Paper 1 worth 100 marks and Paper 2 worth 200 marks. Paper 1 consisted of 50 objective type questions, whereas Paper 2 comprised 100 questions. Each question carried a weightage of two marks.
For other related details and information, candidates are advised to refer to the official website of KEA.
function loadGtagEvents(isGoogleCampaignActive) { if (!isGoogleCampaignActive) { return; } var id = document.getElementById('toi-plus-google-campaign'); if (id) { return; } (function(f, b, e, v, n, t, s) { t = b.createElement(e); t.async = !0; t.defer = !0; t.src = v; t.id = 'toi-plus-google-campaign'; s = b.getElementsByTagName(e)[0]; s.parentNode.insertBefore(t, s); })(f, b, e, ' n, t, s); };
function loadSurvicateJs(allowedSurvicateSections = []){ const section = window.location.pathname.split('/')[1] const isHomePageAllowed = window.location.pathname === '/' && allowedSurvicateSections.includes('homepage')
if(allowedSurvicateSections.includes(section) || isHomePageAllowed){ (function(w) { var s = document.createElement('script'); s.src=" s.async = true; var e = document.getElementsByTagName('script')[0]; e.parentNode.insertBefore(s, e); })(window); }
}
window.TimesApps = window.TimesApps || {};
var TimesApps = window.TimesApps;
TimesApps.toiPlusEvents = function(config) {
var isConfigAvailable = "toiplus_site_settings" in f && "isFBCampaignActive" in f.toiplus_site_settings && "isGoogleCampaignActive" in f.toiplus_site_settings;
var isPrimeUser = window.isPrime;
if (isConfigAvailable && !isPrimeUser) {
loadGtagEvents(f.toiplus_site_settings.isGoogleCampaignActive);
loadFBEvents(f.toiplus_site_settings.isFBCampaignActive);
loadSurvicateJs(f.toiplus_site_settings.allowedSurvicateSections);
} else {
var JarvisUrl="
window.getFromClient(JarvisUrl, function(config){
if (config) {
loadGtagEvents(config?.isGoogleCampaignActive);
loadFBEvents(config?.isFBCampaignActive);
loadSurvicateJs(config?.allowedSurvicateSections);
}
})
}
};
})(
window,
document,
'script',
);
[ad_2]
Source link
